Question

find k if (x-1) is a factor of 2x2 + kx + √2

Answer 1

Step-by-step explanation:

x-1=0

x=1

$2 {x}^{2} + kx + \sqrt{2}$

$2 {(1)}^{2} + k(1) + \sqrt{2} = 0$

$2 + k+ \sqrt{2} = 0$

$k = - 2 - \sqrt{2}$

Answer 2

Answer: If (x-1) is a factor of 2x² + kx + √2

p(1) = 2x² + kx + √2

p(1) = 2(1³) + k(1) + √2

= 2 + k + √2

-2 - √2 = k