Question

find K if x=2 is a 0 of polynomial x³ - x² -kx + 24​

Answer 1

Answer:

x = 2

2^3 - 2^2 - k.2 + 24

8 - 4 - 2k + 24

4 - 2k + 24

28 - 2k

-2k = -28

k = 14

hope it helps

Answer 2

Given x=2 is a zero of polynomial p(x) = x^3 - x^2 - kx + 24

Therefore, substituting x = 2 in p(x)

p(2) = (2)^3 - (2)^2 - k(2) + 24 = 0

p(2) = 8 - 4 - 2k + 24 = 0

- 2k + 28 =0

k = 14