Question

find k if x+2 is a factor of 2x^3-3kx^2+x-5​

Answer 1

x = -2 (Since "x+2" is a factor of the equation)

If -2+2 = 0 then,

0 = 2x^3-3kx^2+x-5

Now put the value of x as -2,

So, 2(-2)^3 - 3k (-2)^2 + (-2) - 5 = 0

2(-8) - 3k(4) -7 = 0

-16 x 3K(4) -7 = 0

3k(4) = 7+16

k = 7+16/4 x 3

k = 23/12