Question

Find ‘k’ if (x – 2) is a factor of x3 – kx2 – 112.

Answer 1

Answer:

-26

Step-by-step explanation:

x-2 is a factor

so x=2

let p(x)= x3-kx2-112

hence p(2)=2^3-4k-112

=8-4k-112

= -4k-104

as p(2)=0

-4k-104=0

-4k=104

k= -104/4

k=-26

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Answer 2

p(x) = x^3-kx^2-112

Since (x-2) is a factor of p(x), then by factor theorem,

p(2)=0

=>2^3-k(2^2)-112=0

=>8-4k-112=0

=>-104-4k=0

=>4k=-104

=>k=-104/4=-26

Thus, value of k=-26

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