Question

find k if x =2 is a root of equation k x²-10x+3=0​

Answer 1

kx²-10x+3=0

x=2

K(2)^2-10(2)+3=0

K(4)-20+3=0

4k-17=0

K=17/4

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Answer 2

Answer:

Step-by-step explanation:

plug in x=2 in the given equation

as 2 is a root plugging x=x in the equation must give us the value of the equation to be 0

so k(4)-10(2)+3=0 which gives us the value as

4k-17=0 so k=17/4

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