Question

find k if x-2 is factor of 3x^4+8x^3-4kx+k​

Answer 1

Answer:

Step-by-step explanation:

p(x) = 3x^4+8x^3-4kx+k​

g(x)= x-2= 0

      x= 2

p(2)= 3(2)^4 + 8(2)³ -4k(2) + k

      = 3(16) + 8(8) - 8k + k

      = 48 + 64 - 7k

      = 112-7k

G(x) is a factor, so remainder is 0.

112-7k = 0

-7k = -112 { minus and minus cancel }

7k = 112

k = 112/7

k=16

∴ k=16

      Hope it helped you. Take care.