Question

find k if x=3 I is a root of equation kx square -10x+3=0

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Answer 1

$\huge{\mathcal{\blue{\underline{Answer}}}}$

$kx {}^{2} - 10x + 3 = 0 \\ k(3) {}^{2} - 10(3) + 3 = 0 \\ 9k - 30 + 3 = 0 \\ 9k - 27 = 0 \\ 9k = 27 \\ k = \frac{27}{9}$

$\huge{\mathcal{\orange{\underline{k=3}}}}$

Answer 2

Step-by-step explanation:

x=3 is root

hence k*3*3-10*3+3=0

9k-30+3=0

9k=27

k=3

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