find k, if x+3 is a factor of 3x²+kx+6
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According to the Remainder theorem, when a polynomial p(x) is divided by (x−a), then the remainder is the value of p(x) at x=a
Here p(x)=3x 2+kx+6
When it is divided by its factor (x+3),
Remainder is =p(−3)=0
3(−3) 2+(−3)k+6=0
27−3k+6=0
33−3k=0
3k=33
k=11
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