find k if x + 3 is a factor x^3+ 3x^2-kx-3
Answers
Let the given polynomial be f(x) = x³ + 3x² - Kx - 3.
Given that x + 3 is a factor of f(3).
In accordance with Factor Theorem,
f(3) = 0
3³ + 3(3)² - 3K - 3 = 0
27 + 3(9) - 3K - 3
3K = 27 + 24
3K = 51
K = 51/3
K = 17.
For K = 17, (x + 3) is a factor of the above polynomial.
Step by step explanation:-
As they given x + 3 is a factor If we substuite that It should be equal to zero because It is a factor of x³+3x²-kx-3
So,
f(x) = x³+3x²-kx-3
f(3) = ?
f(x) = x³+3x²-kx-3
f(3) =0
x³+3x²-kx-3
(3)³ +3(3)²-k(3)-3 =0
27 +27 -3k -3 =0
54-3-3k =0
51 -3k =0
51 = 3k
k = 17
So, value of k is 17
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Know more about cubic polynomial:-
The polynomial whose degree is equal to 3 is called cubic polynomial
It has 3 factors
Its general form is ax³+bx²+cx+d
a is not equal to 0
Graph of cubic polynomial is cubic graph
Relation ship between zeroes &coefficients of cubic polynomial
Let α,ß, γ are roots of cubic polynomial
Sum of roots = -b/a
α, + ß, + γ = -b/a
Sum of product of roots two taken at a time = c/a
αß + ßγ + γα = c/a
Product of roots = -d/a
αßγ = -d/a
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Hope my answer helps to u