Question

find K if x = 3 is the root of equation kx square - 10 X + 3=0​

Answer 1

$\huge{\mathcal{\blue{\underline{Answer}}}}$

$kx {}^{2} - 10x + 3 = 0 \\ k(3) {}^{2} - 10(3) + 3 = 0 \\ 9k - 30 + 3 = 0 \\ 9k - 27 = 0 \\ 9k = 27 \\ k = \frac{27}{9}$

$\huge{\mathcal{\orange{\underline{k=3}}}}$

Answer 2

Explanation:

kx square - 10 X + 3=0

9k-30+3=0

9k=27

k=3

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