find k if x=4 is one of the root of 4x^2-kx-16=0
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=>4x^2-kx-16=0
substitute value of x
=>4(4)^2-k*4-16=0
=>64-4k-16=0
=>48-4k=0
=>4k=48
k=12
Thank you
Answered by
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Answer:
Given: quadratic equation kx
2 +4x+1=0, has real and distinct roots
To find the value of k
Sol: An equation has real and distinct roots if the discriminant b
2 −4ac>0
In the given equation, a=k,b=4,c=1
Therefore the discriminant is 4
2−4(k)(1)>0
16−4k>0
⟹4k<16
Therefore, k<4
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