Question

* Find k if x=9 is a root of equation
kx² - 10x+3=0​

Answer 1

Answer:

kx^2-10x+3=0

k(9)^2-10(9)+3=0

81k-90+3=0

81k-87=0

81k=87

k=87/81

Answer 2

x =9 is the root of the equation kx²-10x+3=0.

putting x=3 in the given equation, we get

k(9)²-10(9)+3=0

81k - 90 +3 =0

81k -87 =0

81k =87

k= 87/81

k= 1.07

I think you question is wrong

your question like this

picture उपर है .................