find k if y+3 is a factor of 3y^2+ky+6
Answers
Answered by
40
solution of your Question is above
Attachments:
Ayexhw:
ooopss
Answered by
49
#ANSWER...!
Find K , if g(y) (y + 3) is a factor of p(y) 3y^2 + ky + 6.
Zero of (y + 3) ..
y + 3 = 0
y = 0 - 3
y = -3
p(-3) = 3*(-3)^2 + k*(-3) + 6 = 0
=> 3*9 + (-3k) + 6 = 0
=> 27 - 3k + 6 = 0
=> 33 - 3k = 0
=> -3k = 0 - 33
=> -3k = -33
=> k = -33/-3
=> k = 11
On verifying the above p(y) by putting the value of k as 11.
p(y) = 3*(-3)^2 + 11*(-3) + 6
= 3*9 + (-33) + 6
= 27 - 33 + 6
= 33 - 33
= 0...
Therefore , k = 11.
Find K , if g(y) (y + 3) is a factor of p(y) 3y^2 + ky + 6.
Zero of (y + 3) ..
y + 3 = 0
y = 0 - 3
y = -3
p(-3) = 3*(-3)^2 + k*(-3) + 6 = 0
=> 3*9 + (-3k) + 6 = 0
=> 27 - 3k + 6 = 0
=> 33 - 3k = 0
=> -3k = 0 - 33
=> -3k = -33
=> k = -33/-3
=> k = 11
On verifying the above p(y) by putting the value of k as 11.
p(y) = 3*(-3)^2 + 11*(-3) + 6
= 3*9 + (-33) + 6
= 27 - 33 + 6
= 33 - 33
= 0...
Therefore , k = 11.
ok send
Which cls ?
10
sry m in 9th
ooh
that atp wala Question
Similar questions