Question

find K in x squer-18x-5k if the zeros are in the ratio 4:5​

Answer 1

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$if \: p \: and \: q \: are \: the \: zeros \: of \: the \: quadratic \: equation \: then \\ ax {}^{2} + bx + c = 0 \\ then \: p + q = \frac{ - b}{a} \: and \: pq = \frac{c}{a} \\ \\ here \: the \: given \: equation \: is \: \\ x {}^{2} - 18x + 5k = 0 \\ theefore \\ pq = 5k \\ now \: given \: \frac{p}{q} = \frac{4}{5} \\ and \: p + q = 18 \\ \\ solving \: these \\ p = 8 \: \: \: and \: \: q = 10\\ k = \frac{80}{5} = 16$

• Hope this helps you sunny.......

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