Question

find k
(k-1)x+3y=7
(k+1)x+6y=(5k-1)​

Answer 1

Answer:

K+1×k+1=9

(K+1)^2=9

K+1=√9

K+1=+-3

Take k+1=3

K=3-1

K=2

K=2. Ans

Take k+1=-3

K=-3-1

K=-4

Now we can check our answer

Putk=2

x+2+1×y=5;2+1×x+9y=8×2-1

x+3y=5;3x+9y=15

x=5-3y;3×5-3y+9y=15

15+6y=15

y=0

Put y=0

x=5-3×0

x=5

Put k=-4

x-3y=5

x=5+3y

Put the value of x in equation

5+3y-3y=5

5=5

Put in 2equation

is not equal Lhs is not equal to Rhs

So the and is k=2

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Answer 2

Answer:

k=3

Step-by-step explanation:

dividing 2nd equation by 2

now comparing coefficient with 1st equation

We get,

$(k - 1) = (k + 1) \div 2$

after simplification we will get

k=3