Math, asked by rsri0255, 5 months ago

find k[k+4]x²+[k+1]x+1=0 has two equal real roots ​

Answers

Answered by harshalgolait7
0

Step-by-step explanation:

Given quadratic equation: (k+4)x2+(k+1)x+1=0. Since the given quadratic equation has equal roots, its discriminant should be zero. Thus, the values of k are 5 and −

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