Question

find k.[k+4]x²+[k+1]x+1=0 has two equal real roots ​

Answer 1

Answer:

(k+4)x2+(k+1)x+1=0. Since the given quadratic equation has equal roots, its discriminant should be zero. Thus, the values of k are 5 and −3. Thus, the equal root of the given quadratic equation is either 1 or −13.