Math, asked by sasibro6846, 1 year ago

find k of the quadratic equation kx2 - 10x +5 =0 has equal roots

Answers

Answered by Anonymous
4
HI MATE,

Kx^2-10x+5=0

a=K,b=-10 and c=5,

Discriminant,D=b^2-4ac

=(-10)^2-4(K)(5)

=100-20K

FOR THE ABOVE EQUATION TO HAVE EQUAL ZEROS,D=0
=>100-20K=0
=>100=20K
=>K=100/20=5
=>K=5

FOR K=5,THE GIVEN EQUATION HAS TWO REAL AND EQUAL ZEROS.

I HOPE IT HELPS YOU!!!
Answered by vanshag2004
1

Answer:

K = 5

Step-by-step explanation:

Kx^2-10x+5=0

a=K,b=-10 and c=5,

Discriminant,D=b^2-4ac

=(-10)^2-4(K)(5)

=100-20K

FOR THE ABOVE EQUATION TO HAVE EQUAL ZEROS,D=0

=>100-20K=0

=>100=20K

=>K=100/20=5

=>K=5

FOR K=5,THE GIVEN EQUATION HAS TWO REAL AND EQUAL ZEROS.

I HOPE IT HELPS YOU!!!

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