find k of the quadratic equation kx2 - 10x +5 =0 has equal roots
Answers
Answered by
4
HI MATE,
Kx^2-10x+5=0
a=K,b=-10 and c=5,
Discriminant,D=b^2-4ac
=(-10)^2-4(K)(5)
=100-20K
FOR THE ABOVE EQUATION TO HAVE EQUAL ZEROS,D=0
=>100-20K=0
=>100=20K
=>K=100/20=5
=>K=5
FOR K=5,THE GIVEN EQUATION HAS TWO REAL AND EQUAL ZEROS.
I HOPE IT HELPS YOU!!!
Kx^2-10x+5=0
a=K,b=-10 and c=5,
Discriminant,D=b^2-4ac
=(-10)^2-4(K)(5)
=100-20K
FOR THE ABOVE EQUATION TO HAVE EQUAL ZEROS,D=0
=>100-20K=0
=>100=20K
=>K=100/20=5
=>K=5
FOR K=5,THE GIVEN EQUATION HAS TWO REAL AND EQUAL ZEROS.
I HOPE IT HELPS YOU!!!
Answered by
1
Answer:
K = 5
Step-by-step explanation:
Kx^2-10x+5=0
a=K,b=-10 and c=5,
Discriminant,D=b^2-4ac
=(-10)^2-4(K)(5)
=100-20K
FOR THE ABOVE EQUATION TO HAVE EQUAL ZEROS,D=0
=>100-20K=0
=>100=20K
=>K=100/20=5
=>K=5
FOR K=5,THE GIVEN EQUATION HAS TWO REAL AND EQUAL ZEROS.
I HOPE IT HELPS YOU!!!
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