Question

find 'k' so, 2k+1 ,3k+1,and 5k-1 in AP??​

Answer 1

Answer:

k = 2

Step-by-step explanation:

According to the condition,

2k+1 ,3k+1,and 5k-1 are in AP.

Common difference = nth term - (n - 1)th term

Thus, common difference,d = 3k + 1 -(2k + 1)

d is also = 5k - 1 - (3k + 1)

Equation (i)

d = 3k + 1 - (2k + 1)

= 3k + 1 - 2k - 1

= k

Equation (ii)

d = 5k - 1 - (3k + 1)

= 5k - 1 - 3k - 1

= 2k - 2

Equation (i) = Equation (ii)

k = 2k - 2

=> k = 2