find
K so that (3K-2), (4K-6) ( k+2) and in AP
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Answer:
k=3
Step-by-step explanation:
a1=(3k-2), a2=(4k-6), a3=(k+2)
a2-a1=a3-a2
(4k-6)-(3k-2)=(k+2)-(4k-6)
4k-6-3k+2=k+2-4k+6
4k-3k-k+4k=2+6+6-2
4k=12
k=12/4
k=3
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