Question

Find k so that equation has equal real roots x^2 + k(4x + k - 1) + 2= 0

Answer 1

Answer:

use D=b²-4ac=0

u will get your answer

Answer 2

Answer:

Step-by-step explanation:

x² + k(4x + k - 1) + 2= 0

x² + 4kx + k² - k + 2 = 0

where , a = 1 ; b = 4k ; c = k² - k + 2

this eq. have equal roots so,

Discrimamnt = 0

b² - 4ac = 0

(4k)² - 4×1×(k² - k + 2)  = 0

16k² - 4k² - 4k + 8 = 0

12k² - 4k + 8 = 0

3k² - k + 2 = 0

there is doubt in your question i hope you write wrong question by mistake