Question

find k so that k-1,k,k+2 are consecutive terms of G.P.​

Answer 1

thank for asking this question

Answer 2

The value of k is 2.

Step-by-step explanation:

If a, b, c are in GP then

$b^2=ac$

It is given that k-1,k,k+2 are consecutive terms of G.P.​

$k^2=(k-1)(k+2)$

$k^2=k^2+2k-k-2$

$k^2=k^2+k-2$

Subtract $k^2$ from both sides.

$k^2-k^2=k^2+k-2-k^2$

$0=k-2$

Add 2 on both sides.

$2=k$

Therefore, the value of k is 2.

#Learn more

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