Question

Find k so that k sq +4k +8,2k sq+ 3k+6, 3k sq+4k+4 are three consecutive terms of an ap

Answer 1

let a=k sq + 4k+8
b=2k sq+3k+6
and c= 3k sq + 4k + 4
now.....for a,b,c to be in ap,
b-a=c-b
Now....
=>2k sq +3k+6 - k sq - 4k+ 8=3k sq+ 4k+4- 2k sq-3k-6
=>k=0

Answer 2

i have solved this question.hope you will understand