CBSE BOARD X, asked by ankitalokhn, 8 hours ago

find k so that kx^2- 6x- 2= 0 have real roots​

Answers

Answered by himanipt7
1

Answer:

Explanation:

kx^{2} -6x-2=0

here, a=k , b=-6 , c=-2

b^{2}- 4ac\geq 0

(-6)^{2} -4\times k \times  (-2)\geq 0

36+8k\geq 0

8k\geq -36

k\geq -\frac{36}{8}

k\geq -\frac{9}{2}

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