Question

Find k so that one root of the equation k(x-1)^2=5x-7 is twice the other

Answer 1

Answer:k = 4, other root = 1

Step-by-step explanation:

x^2 - 5x + k = 0

4^2 - 5×4 + k = 0

16-20+k=0

k =4

Now,

x^2 - 5x + 4 = 0

x^2 -4x-x + 4 = 0

x(x-4)-1(x-4)=0

(x-4)(x-1)=0

x = 4,1

So other root is 1

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