Find k so that one root of the equation k(x-1)^2=5x-7 is twice the other
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Answer:k = 4, other root = 1
Step-by-step explanation:
x^2 - 5x + k = 0
4^2 - 5×4 + k = 0
16-20+k=0
k =4
Now,
x^2 - 5x + 4 = 0
x^2 -4x-x + 4 = 0
x(x-4)-1(x-4)=0
(x-4)(x-1)=0
x = 4,1
So other root is 1
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