find k so that quadratic equation has equal roots 2x^2 - (k-2)x+1=0
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if -b/a=c/a then ax²+bx+c=0 has equal roots
nowa=2,b=-(k-2),c=1
-(k-2)/2=1/2
-(k-2)=1
k-2=-1
k=-1+2=1
nowa=2,b=-(k-2),c=1
-(k-2)/2=1/2
-(k-2)=1
k-2=-1
k=-1+2=1
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