Question

Find K so that the equations : x + y = 2, y + z = 3 and x - z = K have a solution.

this is a question from determinant chapter​

Answer 1

:

0

Step-by-step explanation:

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MATHS

For what values of k, the system of linear equations

x+y+z=2

2x+y−z=3

3x+2y+kz=4

has a unique solution?

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VIDEO EXPLANATION

ANSWER

From x+y+z=2 , we get x=2−y−z , substitute this in remaining two equations , we get

2(2−y−z)+y−z=3 , which implies y+3z=1.............................................1)

3(2−y−z)+2y+kz=4 , which implies y+(3−k)z=2..............................2)

subtract equation 2) from 1), we get kz=−1 , which gives z=−

k

1

Therefore for k



=0 , the system of equations have unique solution.