Question

Find k so that the real number – ½ is a zero of the polynomial g(x) = 5x3 – 6kx2 + 9kx – ½ .​

Answer 1

hope this helps you this is your solution

Answer 2

g(-1/2) = 5(-1/2)³ - 6k(-1/2)² + 9k(-1/2) -1/2

= 5(-1/8) -6k(1/4) - 9k/2 -1/2 = 0

= -5/8 - 2k/3 - 9k/2 - 1/2

= -9/8 - 4k-27k/6

= -9/8 - 31k/6 = 0

= -9/8 = 31k/6

= k = -9 *6/ 8*31

= -54/248

k = -27/124