Find k so that x2 + 2x + k is a factor of 2x4 + x3 –14 x2 + 5x + 6. Also find all the zeroes of the two polynomials.
Answers
Answer:
If g(x)=x2 + 2x + k is a factor of f(x) = 2x4 + x3 - 14x2 + 5x + 6
Then remainder is zero when f(x) is divided by g(x)
Let quotient =Q and remainder =R
Let us now divide f(x) by gx)
R = x(7k + 21) + (2k2 + 8k + 6) -------(1)
and Q = 2x2 - 3x - 2(k + 4).------------(2)
⇒x (7k + 21) + 2 (k2 + 4k + 3) = 0
⇒7k + 21 = 0 and k2 + 4k + 3 = 0
⇒ 7(k + 3) = 0 and (k + 1) (k + 3) = 0
⇒ k + 3 = 0
⇒k = -3
Substituting the value of k in the divider x2 + 2x + k, we obtain: x2 + 2x - 3 = (x + 3) (x - 1) as the divisor.
Hence two zeros of g(x) are -3 and 1.------(3)
Putting k=-3 in (2) we get
Q = 2x2 - 3x - 2
= 2x2 - 4x + x - 2
= 2x(x - 2) + 1 (x - 2)
= (x - 2)(2x + 1)
Q=0 if x-2=0 or 2x+1=0
So other two zeros of f(x) are 2 and -12-------(4)
As g(x) is a factor of f(x) so zeros of G(x) are zeros of f(x) also
Hence from (3) and (4) we get
The zeros of f(x) are: -3 ,1,, 2 and 12