Find k such that 2 ,k , 5k are the 3 consecutive terms of an A.P.
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Answer:
a1= 2, a2 = k, a3 = 5k
In an AP, a2- a1 = a3 - a2
k - 2 = 5k -k
k-2 = 4k
k- 4k =2
-3k = 2
k = 2 / -3
I hope this is useful..Pls mark me the brainliest answer
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