Question

find k such that that k+ 90 ,k-6and 4 from the consecutive terms of a GP

Answer 1

the value of k is 16

Answer 2

$aq... \frac{k - 6}{k + 9} = \frac{4}{k - 6} \\ .. {k}^{2} + 36 - 12k = 4k + 36 \\ {k}^{2} - 12k = 4k \\ {k}^{2} = 16k \\ k = 16$
so..term are 25 , 10 , 4