Question

Find k such that the difference between the roots of 5x square -kx 1=0 is 1

Answer 1

Answer:

is it -kx+1 ,if so answer is

$+ - 5$

Step-by-step explanation:

$let \: the \:root \: be \: \alpha \: and \: \beta \: \\ so \: there \: difference \: wll \: be \: \\ \alpha - \beta = | \sqrt{d \div a} | \\ or \: \alpha - \beta = ( {k}^{2} - 20) \div 5 \\ or \: 1 = ( {k}^{2} - 20 ) \div 5 \\ or \: 5 = {k}^{2} - 20 \\ or \: {k}^{2} = 25 \\ or \: k = + - 5$

please follow me and upvote