Find k value for a quadratic equation 2x²-kx+k=0 has equal roots
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Find k value for a quadratic equation⠀ 2x² - kx + k = 0 has equal roots
Given equation is 2x² - kx + k = 0
On comparing with ax² + bx + c = 0,⠀⠀ we get a = 2, b = -k and c = k
For equal roots, the discriminant must be zero
i.e., D = b² - 4ac = 0
=> (-k)² - 4(2)k = 0
=> k² - 8k = 0
=> k(k - 8) = 0
Therefore, k = 0, 8
Hence, the required values of k are 0 and 8.
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