Question

Find k value for a quadratic equation 2x²-kx+k=0 has equal roots

Answer 1

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Answer 2

$\bf\huge\underline{Question}$

Find k value for a quadratic equation⠀ 2x² - kx + k = 0 has equal roots

$\bf\huge\underline{Answer}$

Given equation is 2x² - kx + k = 0

On comparing with ax² + bx + c = 0,⠀⠀ we get a = 2, b = -k and c = k

For equal roots, the discriminant must be zero

i.e., D = b² - 4ac = 0

=> (-k)² - 4(2)k = 0

=> k² - 8k = 0

=> k(k - 8) = 0

Therefore, k = 0, 8

Hence, the required values of k are 0 and 8.