Question

find k value for a quadratic equation 9x²-3kx+k=0 has equal roots

Answer 1

here is Ur answer mate

Answer 2

Answer:0 v 4

Step-by-step explanation:

9x²-3kx+k=0

If the equation has real roots then b²-4ac>0

b²-4ac=(-3k)²-4(9)(k)

=> =9k²-36k>0

=>k(9k-36)=0

=>k=0 v 9k-36=0

=>k=0 v 9k=36

=>k=0 v k=36/9=4

=>k=0 v k=4