find k value if 9xsquare+kx+1=0
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Step-by-step explanation:
The given equation if 9x2+kx+1=0
comparing with ax2+bx+c=0
here a=9, b=k , c=1
△ = b2−4ac
= k2−4(9)(1)
= k2−36
The roots are equal so △ must be zero
∴ = k2−36=0
= (x+6)(x−6)=0
=x+6=0 or x−6=0
∴ k=−6 or k=6
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