Question

find k which kx +y=k²and x+ky=1 have infinitely many solutions

Answer 1

a1 = k               a2 = 1
b1 = 1               b2 = k
c1 = k^2            c2 = 1
 
for infinitely many solutions 
                            a1 / a2  = b1 / b2 = c1 / c2
                            k / 1  =  1 / k  =  k^2 / 1
  Now , 
             k / 1  = 1 / k
                k^2 = 1
                  k  = + 1 , -1
           
            1 / k = k^2 / 1
             k^3 = 1

          k / 1 = k^2 / 1 
              k  = 1

therefore , 
                  k = +1 and -1  

Answer 2

This is the ans .
Mark it as brainliest plzz