Question

find kinetic energy, electrostatic potential energy and total. energy of single electron in 2nd excited state of Li^(+2) atom.

Answer 1

Explanation:

CHEMISTRY

The total energy of an electron in the second excited state of the hydrogen atom is about −1.5eV. The kinetic energy and potential energy of the electron in this state are:

November 22, 2019avatar

Noor Arekar

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ANSWER

For an electron in an atom Total energy = Kinetic energy + Potential energy.

From Bohr's model,

Potential energy =(−2)× Kinetic energy ,

So, Total energy = Kinetic energy −2 Kinetic energy

Hence, Kinetic energy =1.5 eV and Potential energy =−3.0 eV

Answer 2

The kinetic energy, electrostatic potential energy and total energy are 13.6ev,-13.6ev and -27.2eV

• Let us go through the given parameter

       Atomic number of Li(+2) atom(Z) = 3

       number of electrons in Li(+2) atom(n)= 3

• Total energy (Etotal)= -13.6 (Z²/n²)

                                                  =-13.6(3²/3²)

                                                  = -13.6ev

      The total energy of the atom is  -13.6ev

• Kinetic energy = I Etotal I

                         =I -13.6 I = 13.6ev

       The kinetic energy of the atom is 13.6ev

• Potential energy = 2×Etotal

                             =2(-13.6ev) = -27.2eV

      The kinetic energy of the atom is  -27.2eV