Question

find L.S.A and T.S.A of a cubical of edges: 4cm​

Answer 1

Answer:

L.S.A of cube= 64 cm

T.S.A of cube= 96cm

Step by Step Explanation:

L.S.A of cube = 4l²

l = 4cm

L.S.A of cube = 4 x (4)²

L.S.A of cube = 4 x 16

L.S.A of cube = 64 cm

T.S.A of cube = 6l²

T.S.A of cube = 6 x (4)²

T.S.A of cube = 6 x 16

T.S.A of cube = 96 cm

Answer 2

Lateral surface area of cube = $\sf {4(edge)}^{2}$

$= \sf4 {(4)}^{2} \\ \sf = 4 \times 16 \\ \sf = 54 {cm}^{2}$

Total surface area of cube = $\sf6 {(edge)}^{2}$

$6 {(4)}^{2} \\ \sf = 6 \times 16 \\ \sf = 96 {cm}^{2}$

$\sf \huge\pink{ \: L.S.A = 54 {cm}^{2} }\\ \sf \huge\pink{ \: T.S.A = 96 {cm}^{2} }$