find lamda if the distance lamda,1and lamda-1is 2√5
Answers
Answered by
0
Answer:
λ
−
1
)
2
+
(
1
−
λ
)
2
=
(
2
√
5
)
2
⇒
λ
2
+
1
−
2
λ
+
λ
2
+
1
−
2
λ
=
20
⇒
2
λ
2
−
4
λ
+
2
−
20
=
0
⇒
2
λ
2
−
4
λ
−
18
=
0
⇒
λ
2
−
2
λ
−
9
=
0
λ
=
2
±
√
4
+
4
×
9
2
=
2
±
√
4
+
36
2
=
2
±
√
40
2
=
2
±
2
√
10
2
=
1 ± √ 10
Step-by-step explanation:
Answered by
4
Answer:
(25)2 it is the answer of this question
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