find Laplace transform
2 sin 4t + 5cos2t
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Answer:
f(t)=2sin4t + 5cos2t
taking Laplace on both side
L{f(t)}=L {2sin4t + 5cos2t}
=2L{sin4t}+ 5L{cos2t}
(sinat=a/s^2+a^2 ,cosat=s/s^2+a^2)
=2 ×(4/s^2+16)+ 5×(s/s^2+ 4)
. =8/s^2+16 + 5s/s^2+4
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