Math, asked by rohanw195, 3 months ago

find Laplace transform
2 sin 4t + 5cos2t​

Answers

Answered by pgarg964
3

I haven't studied this topic

Answered by silveryshades26
1

Answer:

f(t)=2sin4t + 5cos2t

taking Laplace on both side

L{f(t)}=L {2sin4t + 5cos2t}

 =2L{sin4t}+ 5L{cos2t}

(sinat=a/s^2+a^2 ,cosat=s/s^2+a^2)

 =2 ×(4/s^2+16)+ 5×(s/s^2+ 4)

. =8/s^2+16 + 5s/s^2+4

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