Question

Find Laplace transform of e^2^t cos^2t

Answer 1

Step-by-step explanation:

L{e^2^t×cos2t}

using first shifting property

L{cos2t}=s/s²+2²

=s/s²+4

then

L{e^2^t×cos2t}=s-2/(s-2)²+4

I hope this helps you