Question

find laplace transform of sin^3 2t

Answer 1

This is pretty simple!

sin^3(2t) = (3*sin(2t)/4) - (sin(3*2t)/4)

Now, by applying laplace transform , we know that LT of

sin (wt) u(t) = w/(s^2+w^2),

our expression becomes,

(3/4)*(2/(s^2+4)) - (1/4)*(6/(s^2+36))

Now,

solve this expression to get

48/(s^4+40s^2+144)

hope this helps.....

and mark me as the brainliestanswer

Answer 2

This is pretty simple!
sin^3(2t) = (3*sin(2t)/4) - (sin(3*2t)/4)
Now, by applying laplace transform , we know that LT of 
sin (wt) u(t) = w/(s^2+w^2),
our expression becomes,
(3/4)*(2/(s^2+4)) - (1/4)*(6/(s^2+36))
Now,
solve this expression to get
48/(s^4+40s^2+144)

A computer based solution to refer to for the correctness of the answer: