Question

find largest number which divides 280 3393 and 532 leaving remainder as 3, 5 and 7 respectively​

Answer 1

Answer:

As per the given data in the question :

1. We will at first subtract the remainders from the numbers

280 – 3 = 277

3393 – 5 = 3388

532 – 7 = 525

2. Now, we will find the factors of the 277, 3388 & 525 by prime factorization method

277 = 277 * 1 ….. [ since 277 is a prime number ]

3388 = 2 * 2 * 7 * 11 * 11 * 1  

525 = 5 * 5 * 3 * 7 * 1

3. The H.C.F. of (277, 3388 & 525) = 1

However on dividing the numbers given in the question i.e., 280, 3393 & 523 by 1, will not leave any remainder.

Hence, as per the data given in the question there is no such number which satisfies the given condition.