Find largest number which divides 957 and 1280 leaving remainder 5 in each case
Answers
Answered by
74
957 - 5 = 952
1280 - 5 = 1275
Find the HCF of 952 and 1275
The HCF = 17
The largest number which divides 952 and 1275 leaving remainder 5 in each case is 17
1280 - 5 = 1275
Find the HCF of 952 and 1275
The HCF = 17
The largest number which divides 952 and 1275 leaving remainder 5 in each case is 17
Answered by
22
Answer:
The largest number which divides the given number 957 and 1280 gives 5 as the remainder is 17.
Solution:
Let the largest number be x.
Given, when 957 is divided by x, it leaves remainder 5
Thus, (957-5) is divisible by x, i.e. 952 is divisible by x.
Given, when 1280 is divided by x, it leaves remainder 5
Thus, (1280-5) is divisible by x, i.e. 1275 is divisible by x.
Hence, x = H. C. F. of 952, 1275.
Factors of 952 = 2 x 2 x 2 x 7 x 17
Factors of 1275 = 3 x 5 x 5 x 17
Thus, the H. C. F. of 952, 1276 = 17.
Thus, the largest number which divides the given number 957 and 1280 gives 5 as the remainder is 17.
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