Question

Find largest number which divjdes438 and606 leaving remainder 6 in each case

Answer 1

Answer: Highest Common Factor(H.C.F) = 24

Step-by-step explanation:

First, Lets find the HCF OF 438 and 606 because in the Qn its mentioned "largest"

First deduct(subtract) 6 from each cases

438-6=432

606-6=600

Prime factorization of 432 = 2 * 2 * 2 * 2 * 3 * 3 * 

Prime factorization of 600 = 2 * 2 * 2 * 3 * 5 * 5

HCF(432,600) = 2 * 2 * 2 * 3

                        = 24.