Find largest three digut no which is a perfect sq. With solvation
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Let's see the numbers:
There are three possibilities:-
1. 30
2. 32
3. 33
NOW SEE THE SQUARE OF EACH NUMBER.
=>30^2 = 900
=> 31^2 = 961
=> 32^2 = 1024
SO THE 1ST POSSIBLE IS WRONG BECAUSE IT IS LESS THAN 961.
AND THIRD ONE IS ALSO WRONG BECAUSE IT HAS 4 DIGITS.
SO WE CONCLUDE THAT 31^2 = 961 WHICH IS RIGHT ANSWER.
BE BRAINLY
Answered by
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ans 931 ok found it give me points
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