Find last digit of the number 3 to the power of 2015
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Answer:
5 is the last digit ...........
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Step-by-step explanation:
we, have to understand that the last digit no. in exponents of 3 are 3,9,7 and 1
3^1=3 3
3^2=9 9
3^3=27 7
3^4=81 1
3^5=243 3
3^6=.....9 9
and so on these 4 numbers can be treated a set of numbers which repeat itself
3^2011=.....3
. ......9
. .....7
. ..... 1
3^2015=....3
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