Find last term of ap a7 d3 n8
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Answer:
a7+[n(d3-a7)^2]
Step-by-step explanation:
an=a+(n-1)d
=a7+(n-1)(d3-a7); a=a7,
d=d3-a7,
n=n.
by simplified above
we get,
=a7+[n(d3-a7)^2]
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