Question

find last two digit ho 7^4032​

Answer 1

cyclicity of 7 = 7 , 9 , 3 , 1

power = 4032

power = 4032/4 = 1008

Since the power is divisible by 4 then the last digit will end with 1

Hope it helps

Mark the brainliest and click the thanks button

And don't forget to follow me