Find LcM & Hcf of 224 and228 also verify
that lcm & HCF = product of the numbers 288 multiplying
by 224
Answers
Answer:
Prime factor of given no.s
Step-by-step explanation:
36=2x2x3x3
84=2x2x3x7
LCM=2x2x3x3x7=252
HCF2x2x3=12
LCMXHCF=1524
PRODUCT=36X48=1524
Hence Proved
ᴀɴsᴡᴇʀ
We know that,
LCM = product of the smallest power of
each common prime factor in the
numbers
HCF = product of the greatest power of
each prime factor involved in the
numbers
_____________________
・prime factors of 224 and 228 are;
224 = 2 × 2 × 2 × 2 × 2 × 7 = 2⁵ × 7
228 = 2 × 2 × 3 × 19 = 2² × 3 × 19
then,
LCM = 2² × 2³ × 7 × 3 × 19
➪ LCM(224,228) = 4 × 8 × 7 × 3 × 19
➪ LCM(224,228) = 32 × 399
➪ LCM(224,228) = 12769
so, LCM of 224 and 228 is 12769
and
HCF = 2²
➪ HCF (224,228) = 4
so, HCF of 224 and 228 is 4
_____________________
we have,
- LCM(224,228) = 12769
- HCF(224,228) = 4
☆ we have to varify product of LCM and HCF = product of Numbers
LCM × HCF = product of numbers
➪ 12769 × 4 = 224 × 228
➪ 51076 = 51076
so, LHS = RHS