Math, asked by bhoomikarmyk, 5 months ago

Find LcM & Hcf of 224 and228 also verify
that lcm & HCF = product of the numbers 288 multiplying
by 224​

Answers

Answered by ramprasadsharma881
0

Answer:

Prime factor of given no.s

Step-by-step explanation:

36=2x2x3x3

84=2x2x3x7

LCM=2x2x3x3x7=252

HCF2x2x3=12

LCMXHCF=1524

PRODUCT=36X48=1524

Hence Proved

Answered by brainlyofficial11
267

ᴀɴsᴡᴇʀ

We know that,

LCM = product of the smallest power of

each common prime factor in the

numbers

HCF = product of the greatest power of

each prime factor involved in the

numbers

_____________________

・prime factors of 224 and 228 are;

224 = 2 × 2 × 2 × 2 × 2 × 7 = 2⁵ × 7

228 = 2 × 2 × 3 × 19 = 2² × 3 × 19

then,

LCM = 2² × 2³ × 7 × 3 × 19

➪ LCM(224,228) = 4 × 8 × 7 × 3 × 19

➪ LCM(224,228) = 32 × 399

➪ LCM(224,228) = 12769

so, LCM of 224 and 228 is 12769

and

HCF = 2²

➪ HCF (224,228) = 4

so, HCF of 224 and 228 is 4

_____________________

we have,

  • LCM(224,228) = 12769
  • HCF(224,228) = 4

☆ we have to varify product of LCM and HCF = product of Numbers

LCM × HCF = product of numbers

➪ 12769 × 4 = 224 × 228

➪ 51076 = 51076

so, LHS = RHS

hence, verified!

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